Verified from official source on 12 Jul 2026
SSC JE Final Result 2026 — Junior Engineer Tentative Allocation Declared, 1,731 Selected (Civil, Mechanical & Electrical)
📍 All IndiaStaff Selection Commission (SSC) — Junior Engineer (Civil, Mechanical & Electrical) Examination 2025, Various Central Govt Departments (CPWD, MES, BRO etc.)Results
- Total Posts
- 1731
- Minimum Qualification
- Diploma / ITI
Overview
The Staff Selection Commission has declared the SSC JE Final Result 2025-26 on 9 July 2026, releasing the First Round of Tentative Allocation (FRTA) for the Junior Engineer (Civil, Mechanical & Electrical) Examination 2025. A total of 1,731 candidates have been provisionally recommended out of 11,052 who submitted their option-cum-preference form.
Candidates whose roll numbers appear in the result PDF must complete two urgent steps. First, participate in the Sliding Process by choosing preferred venue, date, and slot through the SSC login portal between 12 July and 14 July 2026 (by 5:00 PM). Second, appear for Identity Verification (IV) in person on 20 or 21 July 2026. Failure to complete either step will result in disqualification from the final allocation. The SSC JE 2025 Paper II exam was conducted on 7 April 2026.
To check the result, visit ssc.gov.in, click Results, go to JE category, and find the link titled "Junior Engineer (Civil, Mechanical & Electrical) Examination, 2025 — List of Shortlisted Candidates." Download the PDF and press Ctrl+F to search your roll number. The minimum qualifying marks in Paper II are 90 marks for UR, 75 for OBC/EWS, and 60 for SC/ST and other categories.
Cut-off Marks
Paper II Minimum Qualifying: UR-90 | OBC/EWS-75 | SC/ST/Others-60
Important Dates
Paper II Exam
07 Apr 2026
FRTA Result Declared
09 Jul 2026
Sliding Process Deadline
14 Jul 2026
Identity Verification 20–21 Jul 2026
To be announced
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